Integrand size = 24, antiderivative size = 74 \[ \int \frac {\sec ^5(c+d x)}{(a+i a \tan (c+d x))^2} \, dx=\frac {3 \text {arctanh}(\sin (c+d x))}{2 a^2 d}+\frac {3 \sec (c+d x) \tan (c+d x)}{2 a^2 d}-\frac {2 i \sec ^3(c+d x)}{d \left (a^2+i a^2 \tan (c+d x)\right )} \]
[Out]
Time = 0.08 (sec) , antiderivative size = 74, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {3581, 3853, 3855} \[ \int \frac {\sec ^5(c+d x)}{(a+i a \tan (c+d x))^2} \, dx=\frac {3 \text {arctanh}(\sin (c+d x))}{2 a^2 d}-\frac {2 i \sec ^3(c+d x)}{d \left (a^2+i a^2 \tan (c+d x)\right )}+\frac {3 \tan (c+d x) \sec (c+d x)}{2 a^2 d} \]
[In]
[Out]
Rule 3581
Rule 3853
Rule 3855
Rubi steps \begin{align*} \text {integral}& = -\frac {2 i \sec ^3(c+d x)}{d \left (a^2+i a^2 \tan (c+d x)\right )}+\frac {3 \int \sec ^3(c+d x) \, dx}{a^2} \\ & = \frac {3 \sec (c+d x) \tan (c+d x)}{2 a^2 d}-\frac {2 i \sec ^3(c+d x)}{d \left (a^2+i a^2 \tan (c+d x)\right )}+\frac {3 \int \sec (c+d x) \, dx}{2 a^2} \\ & = \frac {3 \text {arctanh}(\sin (c+d x))}{2 a^2 d}+\frac {3 \sec (c+d x) \tan (c+d x)}{2 a^2 d}-\frac {2 i \sec ^3(c+d x)}{d \left (a^2+i a^2 \tan (c+d x)\right )} \\ \end{align*}
Time = 0.76 (sec) , antiderivative size = 146, normalized size of antiderivative = 1.97 \[ \int \frac {\sec ^5(c+d x)}{(a+i a \tan (c+d x))^2} \, dx=-\frac {\sec ^2(c+d x) \left (8 i \cos (c+d x)+3 \log \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )+3 \cos (2 (c+d x)) \left (\log \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )-\log \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )\right )-3 \log \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )+2 \sin (c+d x)\right )}{4 a^2 d} \]
[In]
[Out]
Time = 0.69 (sec) , antiderivative size = 89, normalized size of antiderivative = 1.20
method | result | size |
risch | \(-\frac {i \left (3 \,{\mathrm e}^{3 i \left (d x +c \right )}+5 \,{\mathrm e}^{i \left (d x +c \right )}\right )}{d \,a^{2} \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )^{2}}+\frac {3 \ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right )}{2 a^{2} d}-\frac {3 \ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right )}{2 a^{2} d}\) | \(89\) |
derivativedivides | \(\frac {\frac {2 \left (-\frac {1}{4}+i\right )}{\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1}-\frac {1}{2 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )^{2}}-\frac {3 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{2}+\frac {2 \left (-\frac {1}{4}-i\right )}{\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1}+\frac {1}{2 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{2}}+\frac {3 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{2}}{a^{2} d}\) | \(102\) |
default | \(\frac {\frac {2 \left (-\frac {1}{4}+i\right )}{\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1}-\frac {1}{2 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )^{2}}-\frac {3 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{2}+\frac {2 \left (-\frac {1}{4}-i\right )}{\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1}+\frac {1}{2 \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{2}}+\frac {3 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{2}}{a^{2} d}\) | \(102\) |
[In]
[Out]
Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 134 vs. \(2 (66) = 132\).
Time = 0.24 (sec) , antiderivative size = 134, normalized size of antiderivative = 1.81 \[ \int \frac {\sec ^5(c+d x)}{(a+i a \tan (c+d x))^2} \, dx=\frac {3 \, {\left (e^{\left (4 i \, d x + 4 i \, c\right )} + 2 \, e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right )} \log \left (e^{\left (i \, d x + i \, c\right )} + i\right ) - 3 \, {\left (e^{\left (4 i \, d x + 4 i \, c\right )} + 2 \, e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right )} \log \left (e^{\left (i \, d x + i \, c\right )} - i\right ) - 6 i \, e^{\left (3 i \, d x + 3 i \, c\right )} - 10 i \, e^{\left (i \, d x + i \, c\right )}}{2 \, {\left (a^{2} d e^{\left (4 i \, d x + 4 i \, c\right )} + 2 \, a^{2} d e^{\left (2 i \, d x + 2 i \, c\right )} + a^{2} d\right )}} \]
[In]
[Out]
\[ \int \frac {\sec ^5(c+d x)}{(a+i a \tan (c+d x))^2} \, dx=- \frac {\int \frac {\sec ^{5}{\left (c + d x \right )}}{\tan ^{2}{\left (c + d x \right )} - 2 i \tan {\left (c + d x \right )} - 1}\, dx}{a^{2}} \]
[In]
[Out]
Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 167 vs. \(2 (66) = 132\).
Time = 0.27 (sec) , antiderivative size = 167, normalized size of antiderivative = 2.26 \[ \int \frac {\sec ^5(c+d x)}{(a+i a \tan (c+d x))^2} \, dx=-\frac {\frac {2 \, {\left (\frac {\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - \frac {4 i \, \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac {\sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} + 4 i\right )}}{a^{2} - \frac {2 \, a^{2} \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac {a^{2} \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}}} - \frac {3 \, \log \left (\frac {\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + 1\right )}{a^{2}} + \frac {3 \, \log \left (\frac {\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - 1\right )}{a^{2}}}{2 \, d} \]
[In]
[Out]
none
Time = 0.47 (sec) , antiderivative size = 95, normalized size of antiderivative = 1.28 \[ \int \frac {\sec ^5(c+d x)}{(a+i a \tan (c+d x))^2} \, dx=\frac {\frac {3 \, \log \left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1\right )}{a^{2}} - \frac {3 \, \log \left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1\right )}{a^{2}} - \frac {2 \, {\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 4 i \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 4 i\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 1\right )}^{2} a^{2}}}{2 \, d} \]
[In]
[Out]
Time = 4.92 (sec) , antiderivative size = 104, normalized size of antiderivative = 1.41 \[ \int \frac {\sec ^5(c+d x)}{(a+i a \tan (c+d x))^2} \, dx=\frac {3\,\mathrm {atanh}\left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )}{a^2\,d}-\frac {\frac {{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3}{a^2}+\frac {\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{a^2}-\frac {{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\,4{}\mathrm {i}}{a^2}+\frac {4{}\mathrm {i}}{a^2}}{d\,\left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4-2\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )} \]
[In]
[Out]